Wednesday, 4 September 2013

Ex 2.3

                                                  Maths NCERT Book Solutions
                                                                  Chapter 2
                                                                   Ex.2.3



Q: 1
Find the remainder when x3 + 3x2 + 3x + 1 is divided by
 
 
Answer
Let p(x) = x3 + 3x2 + 3x + 1.
(i)     x + 1
        Zero of x +1 is-1.
        i.e. p(-1) = (- 1)3 + 3 (- 1)2 + 3 (-1) + 1 = 0
        So, the remainder is 0.
 
(ii)    
 
         Zero of   is Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mn»1«/mn»«mn»2«/mn»«/mfrac»«/math»
         
(iii)     x
          Zero of x is 0.
          p(0) = (0)3 + 3(0)2 + 3(0) + 1 = 1
          So, the remainder is 1.
 
(iv)     x + Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»
          Zero of x + Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math» is:
          x + Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math» = 0 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#8658;«/mo»«/math» x = - Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»
          p (- Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math») = (- Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»)3 + 3(- Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»)2 + 3(- Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math») + 1 = - Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»3 + 3 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»2 - 3«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math» + 1
          So, the remainder is - Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»3 + 3 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math»2 - 3«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»§#960;«/mi»«/math» + 1
 
(v)      5 + 2x
          Zero of 5+2x  is:
          5 + 2x = 0 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#8658;«/mo»«/math» 2x = - 5
          i.e. x = - Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mn»5«/mn»«mn»2«/mn»«/mfrac»«/math»
          




Q: 2
Find the remainder when x3 - ax2 + 6x - a is divided by x - a.
 
Answer
According to the remainder theorem, if p(x) is any polynomial of degree Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#8805;«/mo»«/math» 1 and a is any real number, then when p(x) is divided by the linear polynomial x - a, then the remainder is p(a).

Here p(x) = x3 - ax2 + 6x - a
        p(a) = (a)3 - a(a)2 + 6a - a
               = 5a
So when x3 - ax2 + 6x - a is divided by x - a, remainder comes to 5a.
OR
By long division
 
 
 
So when x3 - ax2 + 6x - a is divided by x - a, remainder comes to 5a.
 
Concept Insight:  The remainder of any polynomial p(x) when divided by another polynomial (ax+b) where a and b are real numbers  is
p(-b/a).
Note that here -b/a  is the zero of polynomial ax+ b.
This question can also be solved using long division method however it is long and time consuming. Chances of making computational error are high in that method.





Q: 3
Check whether 7 + 3x is a factor of 3x3 + 7x.
 
Answer
Zero of 7 + 3x is:
7 + 3x = 0
Therefore, 
7+3x can be a factor of p(x) = 3x3 + 7x only if  
Here p(x) = 3x+ 7x
 
 7 + 3x is not a factor of 3x3 + 7x.
 
OR
Let us divide (3x3 + 7x) by (7 + 3x). If remainder comes out to be 0 then  7 + 3x will be a factor of
3x3 + 7x.

By long division
 
 
 
As remainder is not zero so 7 + 3x is not a factor of 3x3 + 7x.

Concept Insight: Any linear polynomial 'ax+b' where a and b are real numbers  is a factor of the polynomial p(x) iff p(-b/a) = 0 i.e  -b/a is a zero of p(x) or both the polynomials has a common zero -b/a. This question can also be solved using long division method. Do not forget to change the sign of terms while subtraction in the long division. 









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