Wednesday, 4 September 2013

Ex 2.5

                                                  Maths NCERT Book Solutions
                                                                  Chapter 2
                                                                   Ex.2.5


Q: 1
Use suitable identities to find the following products:
 
 
Answer
(i).    By using identity 
 
        
(ii).    By using identity 
 
         
 
(iii).    
 
 
           By using the identity  
           
 
(iv).    By using identity 
 

          
 
(v).    By using identity 
 
         
 
 
Concept Insight: If the value of the two terms of the binomials are equal then use the algebraic identity (x+a) (x-a) = x2 - a2 else use (x+a) (x+b) = x2+(a+b)x+ab to obtain required product. 




Q: 2
Evaluate the following products without multiplying directly:

    (i)    103 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» 107        (ii)    95 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» 96    (iii)    104 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» 96
 
Answer
(i).    103 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» 107 = (100 + 3) (100 + 7)
                          = (100)2 + (3 + 7) 100 + (3) (7)
        [By using the identity, , where

        x = 100, a = 3 and b = 7]
                          = 10000 + 1000 + 21
                          = 11021
(ii).   95 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» 96 = (100 - 5) (100 - 4)
                    = (100)2 + (- 5 - 4) 100 + (- 5) (- 4)
        [By using the identity, , where

        x = 100, a = - 5 and b = - 4]
                    = 10000 - 900 + 20
                    = 9120
(iii).  104 Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» 96 = (100 + 4) (100 - 4)
                    = (100)2 - (4)2           


                    = 10000 - 16
                    = 9984
 
Concept Insight: The key is to use the algebraic identity (x+a) (x+b) = x2+(a+b)x+ab or (x+a) (x-a) = x2 - a2  for such questions. Write each of the numeral as  100 Â± k ,  or any other suitable number whose square can be easily computed. 




Q: 3
Factorise the following using appropriate identities:
 
 
Answer
 
Concept Insight: Use the appropriate square identity.  If the polynomial has only two terms, reduce each term to the perfect square and use the algebraic identity . When the polynomial has three terms and the term having
 
unit power of each variable has negative sign use the square identity  else use  .




Q: 4
Expand each of the following, using suitable identities:
 
 
Answer
 
 
Concept Insight: Use the algebraic identity  
 
. Do consider the sign of terms while multiplying and squaring.





Q: 5
 
Answer
 
Concept Insight: Use the algebraic identity  
 
  in the reverse order. Write each term as per the terms of the standard identity. Do consider the sign of terms involved.





Q: 6
 
Answer
 
Concept Insight: Since the expressions involves cube so cubic identity will be used.  If the terms of the given polynomial are separated by positive sign use the identity   or if  negative signs are used  then use . Carefully apply the mathematical operations.





Q: 7
Evaluate the following using suitable identities:

(i).  (99)3        (ii).  (102)3        (iii).  (998)3
 
Answer
We know that
 
 
(i)    (99)3 = (100 - 1)3
                = (100)3 - (1)3 - 3(100) (1) (100 - 1)
                = 1000000 - 1 - 300(99)
                = 1000000 - 1 - 29700
                = 970299

(ii)    (102)3 = (100 + 2)3
                  = (100)3 + (2)3 + 3(100) (2) (100 + 2)
                  = 1000000 + 8 + 600 (102)
                  = 1000000 + 8 + 61200
                  = 1061208


(iii)    (998)3 = (1000 - 2)3
                   = (1000)3 - (2)3 - 3(1000) (2) (1000 - 2)
                   = 1000000000 - 8 - 6000(998)
                   = 1000000000 - 8 - 5988000
                   = 1000000000 - 5988008
                   = 994011992
 
 
Concept Insight: Use the cubic identity  and  . Write the numerical term as something added or
 
subtracted from 10,100, 1000 or higher powers of 10 as it's easy to compute higher powers of 10. Carefully apply the mathematical operations.




Q: 8
 
Answer
 
 
Concept Insight: Since all the polynomial given here has degree 3 so cubic identities would be used here. Now if all the terms of the given polynomial are positive  then use identity   while if any two terms has negative sign reduce each of
 
the term of the polynomial as per the standard cubic identity  . 






Q: 9
 
Answer
 
Concept Insight: When the two terms of the polynomial are separated by positive sign use the identity   and when by negative sign use .
 
Carefully take the common term out.





Q: 10
 
Answer
 
Concept Insight: Reduce the terms of the polynomial to perfect cube and then if the two terms of the polynomial are separated by positive sign use the identity   and when by negative sign use  .





Q: 11
Factorise: 27x3 + y3 + z3 -9xyz
 
Answer
We Know that
        
 
Concept Insight: Reduce each terms of the polynomial as per the left hand side of the standard identity,   .





Q: 12
 
Answer
We know that
 
                         
 
Concept Insight: Since the left hand side of the identity resembles the left hand side of identity,  , so this identity
 
will be applicable here. Now the right hand side of the above identity can be written into many forms we need to look at what is required to proved, Accordingly apply  mathematical simplifications and square identities to get the desired result.





Q: 13
 
Answer
 
Concept Insight: Use the result that    for x + y + z = 0.





Q: 14
Without actually calculating the cubes, find the value of each of the following:
 
Answer
 
Concept Insight: Use the result   since x + y + z = 0. Also consider the
 
sign of the term. Carefully do the computation.





Q: 15
Give possible expressions for the length and breadth of each of the following rectangle, in which their areas are given:
 
 
Answer
We know that,
 Area = length Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» breadth
 
Concept Insight: For such questions factorise the expression, given for the area of rectangle by splitting the middle term. One of its factors will be its length and the other will be its breadth.




Q: 16
What are the possible expressions for the dimensions of the cuboids whose volumes are given below?
 
 
Answer
We know that,
Volume of cuboid = length Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» breadth Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math» height
(i).    

        So, the possible solutions is
        Length = 3, breadth = x, height = x - 4
 
        
 
Concept Insight: For such questions factorise the expression, given for the volume of the cuboid by taking the common term out if it has two terms and by splitting the middle term if the polynomial has three terms. Three factors obtained will be its length  breadth and  height.